$eye=$eye->field('id,addtime,adescribe,score,photodir,photoname,ishead,status')->select();可以查询出来array(28) {
[0] => array(8) {
["id"] => string(1) "1"
["addtime"] => string(10) "1379652869"
["score"] => string(5) "70.90"
["status"] => string(1) "2"
["adescribe"] => string(21) "这是第一个示例"
["photodir"] => string(6) "201309"
["photoname"] => string(17) "523bd4b9282da.jpg"
["ishead"] => string(1) "0"
}如果查询时加入where条件:where('ishead=0')可以查询出来数据,但如果加入where条件where('status=2')就出不出来了,我开始以为是status是关键字,改掉还是不行,这是怎么回事?
最佳答案
