求助这个输出到模版的代码有没办法合并呢?

浏览:137 发布日期:2019/12/29 分类:求助交流
1 2 3 4 5 是id 可以获取的

$ad1 = $db_ad -> where(array('id' => "1")) -> find();
$ad1 = $ad1["code"];
$this->assign("ad1",$ad1);

$ad2 = $db_ad -> where(array('id' => "2")) -> find();
$ad2 = $ad2["code"];
$this->assign("ad2",$ad2);

$ad3 = $db_ad -> where(array('id' => "3")) -> find();
$ad3 = $ad3["code"];
$this->assign("ad3",$ad3);

$ad4 = $db_ad -> where(array('id' => "4")) -> find();
$ad4 = $ad4["code"];
$this->assign("ad4",$ad4);

$ad5 = $db_ad -> where(array('id' => "5")) -> find();
$ad5 = $ad5["code"];
$this->assign("ad5",$ad5);
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