$count = User::count();
if($count > 0 ) {
$res = LeftMenu::where('level',1)->select();
$data="";
foreach($res as $key => $val){
//2级
$res2 = LeftMenu::where('pid',$val['id'])->order('id', 'asc')->select();
$data2="";
foreach($res2 as $k2 => $v2){
//3级
$res3 = LeftMenu::where('pid',$v2['id'])->order('id', 'asc')->select();
$data3="";
foreach($res3 as $k3 => $v3){
$data3[$k3]['title']=$v3['title'];
$data3[$k3]['name']=$v3['name'];
$data3[$k3]['icon']=$v3['icon'];
$data3[$k3]['jump']=$v3['jump'];
$data3[$k3]['title']=$v3['title'];
$data3[$k3]['status']=$v3['status'];
$data3[$k3]['rule']=$v3['rule'];
$data3[$k3]['param']=$v3['param'];
// dump($res3);die;
}
$data2[$k]['title']=$v2['title'];
$data2[$k]['name']=$v2['name'];
$data2[$k]['spread']= true;
$data2[$k]['icon']=$v2['icon'];
$data2[$k]['jump']=$v2['jump'];
$data2[$k]['status']=$v2['status'];
$data2[$k]['rule']=$v2['rule'];
$data2[$k]['param']=$v2['param'];
$data2[$k]['list']=$data3;
// dump($res2);die;
}
$data['name']=$val['name'];
$data['title']=$val['title'];
$data['icon']=$val['icon'];
$data['jump']=$val['jump'];
$data['spread']= true;
$data['status']=$val['status'];
$data['rule']=$val['rule'];
$data['param']=$val['param'];
$data['list']=$data2;
dump($count);dump($val);dump($key);die;
}
return $data;
}以下是controller下menu方法 $Leftmenus = new Leftmenumodel;
$res = $Leftmenus->menu();
if(!$res){
$this->return_msg(400,'系统错误，请重试！');
}else{
$this->return_msg(200,'',$res);
}数据库结构
想要实现的api结构
报错1
该如何修改，才能得到想要的API数据结构？求大神指导。
最佳答案
