代码一
<?php
header("Content-type:text/html;charset=utf-8");
function get_week($year) {
$year_start = $year . "-01-01";
$year_end = $year . "-12-31";
$startday = strtotime($year_start);
if (intval(date('N', $startday)) != '1') {
$startday = strtotime("next monday", strtotime($year_start)); //获取年第一周的日期
}
$year_mondy = date("Y-m-d", $startday); //获取年第一周的日期
$endday = strtotime($year_end);
if (intval(date('W', $endday)) == '7') {
$endday = strtotime("last sunday", strtotime($year_end));
}
$num = intval(date('W', $endday));
for ($i = 1; $i <= $num; $i++) {
$j = $i -1;
$start_date = date("Y-m-d", strtotime("$year_mondy $j week "));
$end_day = date("Y-m-d", strtotime("$start_date +6 day"));
$week_array[$i] = array (
str_replace("-",
".",
$start_date
), str_replace("-", ".", $end_day));
}
return $week_array;
}
$weeks = get_week(2011);
echo '第18周开始日期：'.$weeks[18][0].'';
echo '第18周结束日期：'.$weeks[18][1];
?>这段代码没有检测闰年，且仅对某些年份有效。比如$weeks = get_week(2012); 就无法运行了代码二
<?php
header("Content-type:text/html;charset=utf-8");
//检查是不是闰年
$time_year=date("Y",time());
var_dump($time_year);
if ($time_year%4==0 && ($time_year%100!=0 || $time_year%400==0)){
$days=366;
}else{
$days=365;
}
$weeks=date("W",mktime(0,0,0,12,31,$time_year)); //计算一年有多少个星期
$time=mktime(0,0,0,1,1,$time_year);//计算当年开始的时间
for($i=0;$i<=$days;$i++){
$time_array[date("W",$time+$i*86400)][]=date("Y-m-d",$time+$i*86400);
}
for($i=1;$i<=$weeks;$i++){
if ($i<10) {
$week_have_days[$i]=$time_array["0".$i];
}else{
$week_have_days[$i]=$time_array[$i];
}
}
//计算出每个星期的开始和结束
for($i=1;$i<=count($week_have_days);$i++){
echo $time_year."的第".$i."周是从"."-".$week_have_days[$i][0]."--到--".$week_have_days[$i][count($week_have_days[$i])-1]."<br>";
}
?>此段代码在计算一年有多少个星期就出现错误，无法运行。----------------------------------------------------------------------------------------------
求完整功能
最佳答案
