$query = "select * from oa_request_def as a inner join (select code,name from app_dict_def where dict_id = 'oa_request_flow_type') as b on a.check_user_method = b.code";能用连贯操作完成的，就用连贯操作完成。。自己写SQL。。不及连贯来得轻松。 最佳答案
$query = "select * from oa_request_def as a inner join (select code,name from app_dict_def where dict_id = 'oa_request_flow_type') as b on a.check_user_method = b.code";能用连贯操作完成的，就用连贯操作完成。。自己写SQL。。不及连贯来得轻松。