function addClick(){
$this->checkTeac_logined();
session_start();
$course=M("Foodplace");
//if(!$data=$course->create()) $this->error("发布失败");
$user=M("Teacher");
$us=$user->where("id='$_SESSION[userid]'")->find();
$data['teacher_name']=$us['name'];
//$a=$data['teacher_name'];
$data['name']=$_POST['place'];
$b=$course->where(array('teacher_name'=>$data['teacher_name'],'name'=>$data['name']))->find();
$a=$course->getLastSql();
if($b)
$this->error('你已经发布过了！！');
//$c=$course->where(array('place'=>$data['place'],'time'=>$data['time']))->find();
//$a=$course->getLastSql();
//if($c)
//$this->error("上课地点有冲突");
if(!$course->add($data)) $this->error("发布失败");
$url=U("publishClick");
$this->assign('jumpUrl',$url);
$this->success($a);
}在这一句中（$course->where(array('teacher_name'=>$data['teacher_name'],'name'=>$data['name']))->find();）为什么我打印的SQL操作是
SELECT * FROM `think_foodplace` WHERE ( `name` = '嘉名扬' )确认data['teacher_name']是有值的。这是为什么呢？还有一个就是CREATE函数失败
最佳答案
