SAE上TP的ajaxReturn返回不了json数据

浏览:934 发布日期:2014/12/08 分类:求助交流 关键字: SAE ajaxReturn
今天部署代码到SAE平台上,又发现了ajaxReturn返回不了json数据的问题,简直崩溃。<script>
         
          $(document).ready(function(){
              
              var data=new 
              
               $("#go").click(function(){
     
               $("#post-status").fadeIn("fast");
     
               $.post("__ROOT__/index.php/Content/save_article",
   
               {url:$("#input-url").val(), uid:$("#user_id").val()},
                      
               function(data){
               
                   console.info(typeof data);
                   
                   $("#post-status").fadeOut("fast");
                   
                
                     var newarticle=" <div class=\"col-sm-6 col-md-4\" id=\" " +data.id+ " \"><div class=\"thumbnail\"><a href=\"article\/"+data.id+"\"><div class=\"caption\"><h3>"+data.title+"<\/h3><\/a><\/div>"+data.image+ "<\/div><\/div>     ";
                    
                     $("#div-list").prepend(newarticle);
                     
                   
                   
               });
                 });
              
            $("#title-input").val('');     
              
          });
         </script>
   $statue="0";
         $divchacter="<div class=\"pic\"> <img src=\"".$image."\" class=\"list-image\"  width=\"228\" @height=\"102\" > </div>";
         }
         $Content=D('Content');
         $Contentback=$Content->add_content($uid,$url,$h1,$divchacter,$content,$time,$statue);
         $data['id']=$Contentback;
         $data['title']=$h1;
         $data['image']=$divchacter;
         $data['content']=$content;
         $data['statue']=$statue;
         $this->ajaxReturn(array(
        'data'=>$data,
        'info'=>1,
        'status'=>1
 ));
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