public function ajaxlogin(){
import('@.Org.UcService');//导入第三方类文件
$ucService = new UcService;
$uidarray = $ucService->uc_login($_POST['username'], $_POST['password']);
echo $uidarray['uid'];
$loginurl=$ucService->uc_synlogin($uidarray['uid']);
echo $loginurl;
} 最佳答案
